Here is my take of it

送交者: InCaseYouLikeIt 2008年4月11日21:09:42 于 [灵机一动]http://www.bbsland.com

回答: 有意思，能不能详细点。由远景城于 2008年4月11日10:19:32:

Label the two sides by X and Y and say the angle between the approaching trajectory and side X is a. Let Vx and Vy be the velocities of the particle parallel to side X and side Y respectively. Then, considering the ratio, we see Vy : Vx = tan(a), i.e., Vy/Vx = tan(a). Then, via ideal reflection, the particle will bounce off the two sides, with a velocity of Vx along the direction parallel to X and a velocity of Vy in the direction parallel to Y. As Vy:Vx = tan(a), the angle between the trajectory and side X remains a.

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Excellent! /无内容 - 远景城 4/12/08 (1)
- Thanks. It's an interesting question. /无内容 - InCaseYouLikeIt 4/12/08 (0)

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